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উৎপাদকে বিশ্লেষণ কর: $3a^3+2a+5$

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ধরি, $f(a)=3a^3+2a+5$

তাহলে,
$f(-1)=3(-1)^3+2(-1)+5$

$=-3-2+5$

$=0$

অর্থাৎ $a=-1$ হলে, প্রদত্ত রাশির মান শূন্য ($0$) হয়।
$a=-1$
বা, $a+1=0$

অর্থাৎ $(a+1)$, $f(a)$ এর একটি উৎপাদক।

এখন,
$3a^3+2a+5$

$=3a^3+3a^2-3a^2-3a+5a+5$

$=3a^2(a+1)-3a(a+1)+5(a+1)$

$=(a+1)(3a^2-3a+5)$ [Answer]

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