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উৎপাদকে বিশ্লেষণ কর: $x^3-x-24$

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ধরি, $f(x)=x^3-x-24$

তাহলে,
$f(3)=3^3-3-24$

$=27-3-24$

$=0$

অর্থাৎ $x=3$ হলে, প্রদত্ত রাশির মান শূন্য ($0$) হয়।
$x=3$
বা, $x-3=0$

অর্থাৎ $(x-3)$, $f(x)$ এর একটি উৎপাদক।

এখন,
$x^3-x-24$

$=x^3-3x^2+3x^2-9x+8x-24$

$=x^2(x-3)+3x(x-3)+8(x-3)$

$=(x-3)(x^2+3x+8)$ [Answer]

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