$\frac{1-cos^260^\circ}{1+cos^260^\circ}+sec^260^\circ$ এর মান কত?
$\frac{1-cos^260^\circ}{1+cos^260^\circ}+sec^260^\circ$ এর মান কত?
1 টি উত্তর পাওয়া গেছে
প্রদত্ত রাশি,
$\frac{1-cos^260^\circ}{1+cos^260^\circ}+sec^260^\circ$
$=\frac{1-\left(\frac12\right)^2}{1+\left(\frac12\right)^2}+\left(2\right)^2$
$=\frac{1-\frac14}{1+\frac14}+4$
$=\frac{\frac{4-1}4}{\frac{4+1}4}+4$
$=\frac{\frac34}{\frac54}+4$
$=\left(\frac34 \times \frac45\right)+4$
$=\frac35+4$
$=\frac{3+20}5$
$=\frac{23}5$
$=4\frac{3}5$
$\therefore$ নির্ণেয় মান $4\frac{3}5$
$\frac{1-cos^260^\circ}{1+cos^260^\circ}+sec^260^\circ$
$=\frac{1-\left(\frac12\right)^2}{1+\left(\frac12\right)^2}+\left(2\right)^2$
$=\frac{1-\frac14}{1+\frac14}+4$
$=\frac{\frac{4-1}4}{\frac{4+1}4}+4$
$=\frac{\frac34}{\frac54}+4$
$=\left(\frac34 \times \frac45\right)+4$
$=\frac35+4$
$=\frac{3+20}5$
$=\frac{23}5$
$=4\frac{3}5$
$\therefore$ নির্ণেয় মান $4\frac{3}5$