1 টি উত্তর পাওয়া গেছে

Left Hand Side

$=\frac{sinA}{1-cosA}+\frac{1-cosA}{sinA}$

$=\frac{sin^2A+(1-cosA)^2}{sinA(1-cosA)}$

$=\frac{sin^2A+(1^2-2 \cdot 1 \cdot cosA + cos^2A)}{sinA(1-cosA)}$

$=\frac{sin^2A+1-2 cosA + cos^2A}{sinA(1-cosA)}$

$=\frac{sin^2A+cos^2A +1-2 cosA}{sinA(1-cosA)}$

$=\frac{1+1-2 cosA}{sinA(1-cosA)}$

$=\frac{2-2 cosA}{sinA(1-cosA)}$

$=\frac{2(1-cosA)}{sinA(1-cosA)}$

$=\frac{2}{sinA}$

$=2 \cdot \frac{1}{sinA}$

$=2 \cdot cosecA$

$=$ Right Hand Side
কমেন্টস

Rules Applied :

  • $(a-b)^2=a^2-2ab+b^2$
  • $sin^2\theta+cos^2\theta=1$
  • $cosec \theta=\frac{1}{sin \theta}$