Left Hand Side
$=\frac{secA}{cosA}-\frac{tanA}{cotA}$
$=\left(\frac{secA}{\frac{1}{secA}}\right)-\left(\frac{tanA}{\frac{1}{tanA}}\right)$
$=\left(secA \times \frac{secA}{1}\right)-\left(tanA \times \frac{tanA}{1}\right)$
$=sec^2A-tan^2A$
$=1$
$=$ Right Hand Side
[ Proved ]