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Left Hand Side

$=tanA \sqrt{1-sin^2A}$

$=tanA \sqrt{cos^2A}$

$=\frac{sinA}{cosA} \cdot cosA$

$=sinA$

$=$ Right Hand Side

[ Proved ]

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Rules Applied :

  • $cos^2\theta = 1 - sin^2\theta$
  • $tan \theta = \frac{sin \theta}{cos \theta}$

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