1 টি উত্তর পাওয়া গেছে

Left Hand Side

$=\frac{cosA}{1-tanA}+\frac{sinA}{1-cotA}$

$=\frac{cosA}{1-\frac{sinA}{cosA}}+\frac{sinA}{1-\frac{cosA}{sinA}}$

$=\frac{cosA}{\frac{cosA-sinA}{cosA}}+\frac{sinA}{\frac{sinA-cosA}{sinA}}$

$=\left(cosA \times \frac{cosA}{cosA-sinA}\right)+$$\left(sinA \times \frac{sinA}{sinA-cosA}\right)$

$=\frac{cos^2A}{cosA-sinA}+\frac{sin^2A}{sinA-cosA}$

$=\frac{cos^2A}{cosA-sinA}-\frac{sin^2A}{cosA-sinA}$

$=\frac{cos^2A-sin^2A}{cosA-sinA}$

$=\frac{(cosA+sinA)(cosA-sinA)}{(cosA-sinA)}$

$=(cosA+sinA)$

$=sinA+cosA$

$=$ Right Hand Side

[ Proved ]

কমেন্টস

Rules Applied :

  • $tan \theta = \frac{sin \theta}{cos \theta}$
  • $cot \theta = \frac{cos \theta}{sin \theta}$
  • $a^2-b^2=(a+b)(a-b)$