Ask a Question

$\left(x+3\right)\left(x-3\right)$ কে $x^2-6$ দিয়ে ভাগ করলে ভাগশেষ কত হবে?

79 views
in Algebra by
retagged by

$\left(x+3\right)\left(x-3\right)$ কে $x^2-6$ দিয়ে ভাগ করলে ভাগশেষ কত হবে?

Options :

  • (A) $-3$
  • (B) $-6$
  • (C) $6$
  • (D) $3$

1 Answer

2 like 0 dislike
by
selected by
 
Best answer
মনে করি,

$x^2-6=0$ [যেখানে, $\left(x^2-6\right)$ একটি সাধারণ গুণিতক]

বা, $x^2=6$

$\therefore x=\sqrt6$

এখন,

$\left(x+3\right)\left(x-3\right)$

= $x^2-3^2$

= $x^2-9$

= $\left(\sqrt6\right)-9$

= $6-9$

= $-3$

Related questions

10.2k questions

10.3k answers

122 comments

25 users

Welcome to QnAfy !

Ask questions, find answers, and spread the light of knowledge like the sun. On QnAfy, only registered users can post questions and answers.

If you are a teacher or student, you may register using your own name, your school/coaching center’s name, or your website’s name to actively contribute by asking or answering questions. This will help increase your or your institution’s visibility, and in the case of a website, it will boost your backlink profile as well.

So, Register Now

fb Group | fb Page
WhatsApp Message
Join Telegram Group

QnAfy – Where curiosity meets clarity.

Categories

For the best experience with math, please rotate your mobile to landscape mode or use a tablet, laptop, or PC for optimal viewing.
Developed by SRIBAS
Powered by Question2Answer
...