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$f(x)=x^2-5x+6$ এবং $f(x)=0$ হলে, $x=$ কত?

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$f(x)=x^2-5x+6$ এবং $f(x)=0$ হলে, $x=$ কত?

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প্রশ্নমতে,
$f(x)=x^2-5x+6=0$

অর্থাৎ,
$x^2-5x+6=0$

বা, $x^2-3x-2x+6=0$

বা, $x(x-3)-2(x-3)=0$

বা, $(x-3)(x-2)=0$

হয়,
$x-3=0$

$\therefore x=3$

অথবা,
$x-2=0$

$\therefore x=2$

সুতরাং, $x=3,2$ [Answer]

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