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দেওখাও যে, $(x+1)(x+2)$$(3x-1)(3x-4)$$=(3x^2+2x-1)$$(3x^2+2x-8)$

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Left Hand Side,

$(x+1)(x+2)(3x-1)(3x-4)$

$=(x+1)(x+2)(3x-1)(3x-4)$

$=(x+1)(3x-1)(x+2)(3x-4)$

$=\left\lbrace x(3x-1)+1\left(3x-1\right)\right\rbrace$$\left\lbrace x(3x-4)+2(3x-4)\right\rbrace$

$=\left(3x^2-x+3x-1\right)$$\left(3x^2-4x+6x-8\right)$

$=\left(3x^2+2x-1\right)$$\left(3x^2+2x-8\right)$

$=$ Right Hand Side

$\therefore (x+1)(x+2)(3x-1)(3x-4)$$=\left(3x^2+2x-1\right)\left(3x^2+2x-8\right)$ [Showed]

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