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সমাধান কর: $(z+1)(z-2)=(z-4)(z+2)$

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সমাধান কর: $(z+1)(z-2)=(z-4)(z+2)$

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$(z+1)(z-2)=(z-4)(z+2)$

বা, $z(z-2)+1(z-2)=z(z+2)-4(z+2)$

বা, $z^2-2z+z-2=z^2+2z-4z-8$

বা, $z^2-z-2=z^2-2z-8$

বা, $z^2-z-z^2+2z=-8+2$

$\therefore z=-6$

সুতরাং নির্ণেয় সমাধান $z=-6$ [Answer]

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