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$m+\frac1m=a$ হলে, $m^3+\frac{1}{m^3}$ এর মান নির্ণয় কর।

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দেওয়া আছে,

$m+\frac{1}{m}=a$

বা, $\left(m+\frac{1}{m}\right)^3=\left(a\right)^3$
[ উভয় পার্শ্বে ঘন করে ]

বা, $m^3+\frac{1}{m^3}+3\cdot m\cdot\frac{1}{m}\left(m-\frac{1}{m}\right)=a^3$

বা, $m^3+\frac{1}{m^3}-3\cdot a=a^3$
[ মান বসিয়ে ]

$\therefore m^3+\frac{1}{m^3}=a^3-3a$

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