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Left Hand Side

$=\frac{secA}{cosA}-\frac{tanA}{cotA}$

$=\left(\frac{secA}{\frac{1}{secA}}\right)-\left(\frac{tanA}{\frac{1}{tanA}}\right)$

$=\left(secA \times \frac{secA}{1}\right)-\left(tanA \times \frac{tanA}{1}\right)$

$=sec^2A-tan^2A$

$=1$

$=$ Right Hand Side

[ Proved ]

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Rules Applied :

  • $cos \theta=\frac{1}{sec \theta}$
  • $cot \theta=\frac{1}{tan \theta}$
  • $sec^2 \theta - tan^2 \theta = 1$

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