Left Hand Side
$=\frac{sinA}{cosecA}+\frac{cosA}{secA}$
$=\left(\frac{sinA}{\frac{1}{sinA}}\right)+\left(\frac{cosA}{\frac{1}{cosA}}\right)$
$=\left(sinA \times \frac{sinA}{1}\right)+\left(cosA \times \frac{cosA}{1}\right)$
$=sin^2A +cos^2A$
$=1$
$=$ Right Hand Side
[ Proved ]