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$i^{−49}$ এর মান কত?

Options :

  • (ক) $-1$
  • (খ) $i$
  • (গ) $1$
  • (ঘ) $-i$

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আমরা জানি, $i=\sqrt{-1}$

বা, $i^2=\left(\sqrt{-1}\right)^2$

বা, $ i^2=-1$

$\therefore -i^2=1$

আবার,
$i=\sqrt{-1}$

বা, $i^4=-1 \cdot -1  \cdot -1  \cdot -1 = (-1)^4 =1$

সুতরাং,

$i^{-49}$

=$\frac{1}{i^{49}}$

=$\frac{1}{i^{48} \cdot i}$

=$\frac{1}{\left(i^{4}\right)^{12} \cdot i}$

=$\frac{1}{\left(1\right)^{12} \cdot i}$

=$\frac{1}{1 \cdot i}$

=$\frac{1}{i}$

=$\frac{-i^2}{i}$

=$-i$

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