$\frac{a}{x}=\frac{m^2+n^2}{2mn}$ হলে $\frac{\sqrt{a+x}}{\sqrt{a-x}}$ কত?
$\frac{a}{x}=\frac{m^2+n^2}{2mn}$ হলে $\frac{\sqrt{a+x}}{\sqrt{a-x}}$ কত?
1 টি উত্তর পাওয়া গেছে
$\frac{a}{x}=\frac{m^2+n^2}{2mn}$
বা, $\frac{a+x}{a-x}=\frac{m^2+n^2+2mn}{m^2+n^2-2mn}$
বা, $\frac{a+x}{a-x}=\frac{\left(m+n\right)^2}{\left(m-n\right)^2}$
বা, $\sqrt{\frac{a+x}{a-x}}=\sqrt{\frac{\left(m+n\right)^2}{\left(m-n\right)^2}}$
$\therefore \frac{\sqrt{a+x}}{\sqrt{a-x}}=\frac{m+n}{m-n}$ [Answer]
বা, $\frac{a+x}{a-x}=\frac{m^2+n^2+2mn}{m^2+n^2-2mn}$
বা, $\frac{a+x}{a-x}=\frac{\left(m+n\right)^2}{\left(m-n\right)^2}$
বা, $\sqrt{\frac{a+x}{a-x}}=\sqrt{\frac{\left(m+n\right)^2}{\left(m-n\right)^2}}$
$\therefore \frac{\sqrt{a+x}}{\sqrt{a-x}}=\frac{m+n}{m-n}$ [Answer]