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সমাধান সেট নির্ণয় কর: $x+\dfrac{1}{x}=2$

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$x+\dfrac{1}{x}=2$

বা, $\dfrac{1}{x}=2-x$

বা, $1=x\left(2-x\right)$

বা, $1=2x-x^2$

বা, $x^2-2x+1=0$

বা, $x^2-2\cdot x\cdot1+1^2=0$

বা, $\left(x-1\right)^2=0$

বা, $\left(x-1\right)\left(x-1\right)=0$

হয়,
$\left(x-1\right)=0$

$\therefore x=1$

অথবা,
$\left(x-1\right)=0$

$\therefore x=1$

সুতরাং নির্ণেয় সমাধান সেট: $\left\lbrace1,1\right\rbrace$ [Answer]

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