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সমাধান কর: $\frac{x-a}{a^2-b^2}=\frac{x-b}{b^2-a^2}$

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$\frac{x-a}{a^2-b^2}=\frac{x-b}{b^2-a^2}$

বা, $\frac{x-a}{a^2-b^2}=\frac{x-b}{-\left(a^2-b^2\right)}$
[উভয় পক্ষকে $a^2-b^2$ দ্বারা গুণ করে]

বা, $x-a=-\left(x-b\right)$

বা, $x-a=-x+b$

বা, $x+x=a+b$

বা, $2x=a+b$

$\therefore x=\frac{a+b}{2}$

সুতরাং নির্ণেয় সমাধান $x=\frac{a+b}{2}$

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