সরল কর: $\left(\frac{a^2b^{-1}}{a^{-2}b}\right)^2$
সরল কর: $\left(\frac{a^2b^{-1}}{a^{-2}b}\right)^2$
2 টি উত্তর পাওয়া গেছে
$\left(\frac{a^2b^{-1}}{a^{-2}b}\right)^2$
$=\left(\frac{a^2\frac{1}{b}}{\frac{1}{a^2}b}\right)^2$
$=\left(\frac{\frac{a^2}{b}^{}}{\frac{b}{a^2}}\right)^2$
$=\left(\frac{a^2}{b}\times\frac{a^2}{b}\right)^2$
$=\left(\frac{a^4}{b^2}\right)^2$
$=\frac{a^8}{b^4}$ [Answer]
$=\left(\frac{a^2\frac{1}{b}}{\frac{1}{a^2}b}\right)^2$
$=\left(\frac{\frac{a^2}{b}^{}}{\frac{b}{a^2}}\right)^2$
$=\left(\frac{a^2}{b}\times\frac{a^2}{b}\right)^2$
$=\left(\frac{a^4}{b^2}\right)^2$
$=\frac{a^8}{b^4}$ [Answer]
$\left(\frac{a^2b^{-1}}{a^{-2}b}\right)^2$
$=\left(\frac{a^2}{a^{-2}}\times\frac{b^{-1}}{b}\right)^2$
$=\left(a^{2-\left(-2\right)}\times b^{-1-1}\right)^2$
$=\left(a^{2+2}\times b^{-1-1}\right)^2$
$=\left(a^4\times b^{-2}\right)^2$
$=a^8\times b^{-4}$
$=a^8\times\frac{1}{b^4}$
$=\frac{a^8}{b^4}$ [Answer]
$=\left(\frac{a^2}{a^{-2}}\times\frac{b^{-1}}{b}\right)^2$
$=\left(a^{2-\left(-2\right)}\times b^{-1-1}\right)^2$
$=\left(a^{2+2}\times b^{-1-1}\right)^2$
$=\left(a^4\times b^{-2}\right)^2$
$=a^8\times b^{-4}$
$=a^8\times\frac{1}{b^4}$
$=\frac{a^8}{b^4}$ [Answer]