$\left(\frac{a^2b^{-1}}{a^{-2}b}\right)^2$
$=\left(\frac{a^2}{a^{-2}}\times\frac{b^{-1}}{b}\right)^2$
$=\left(a^{2-\left(-2\right)}\times b^{-1-1}\right)^2$
$=\left(a^{2+2}\times b^{-1-1}\right)^2$
$=\left(a^4\times b^{-2}\right)^2$
$=a^8\times b^{-4}$
$=a^8\times\frac{1}{b^4}$
$=\frac{a^8}{b^4}$ [Answer]