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সমাধান কর: $4^x=8$

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$4^x=8$

বা, $\left(2^2\right)^{x}=2^3$

বা, $2^{2x}=2^3$

বা, $2x=3$

$\therefore x=\frac32$

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Rules Applied:

  • $\left(a^{m}\right)^{n}=a^{mn}$
  • $a^x=a^y\Rightarrow x=y$

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