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সমাধান কর: $2^{2x+1}=128$

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$2^{2x+1}=128$

বা, $2^{2x+1}=2^7$

বা, $2x+1=7$

বা, $2x=7-1$

বা, $2x=6$

বা, $x=\frac62$

$\therefore x=3$ [Answer]

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