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$x^2–7x+12\leq0$ এর সমাধান সেট কী?

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$x^2–7x+12\leq0$

বা, $x^2–3x–4x+12\leq0$

বা, $x(x–3)–4(x-3)\leq0$

বা, $(x–3)(x-4)\leq0$

হয়,
$(x–3)\leq0$

$\therefore x\leq3$

অথবা,
$(x–4)\leq0$

$\therefore x\leq4$

সুতরাং, $x^2–7x+12\leq0$ এর সমাধান সেট হচ্ছে $[3,4]$

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