Question

সরল কর : $\left(0.\dot3\times0.8\dot3\right)\div$$\left(0.5\times0.\dot1\right)+$$0.3\dot5\div0.0\dot8$

গণিত : ৯ম-১০ম শ্রেণি : বাস্তব সংখ্যা : সমাধান - পেতে এখানে ক্লিক করুন।

Answer 1

$\left(0.\dot3\times0.8\dot3\right)\div$$\left(0.5\times0.\dot1\right)+$$0.3\dot5\div0.0\dot8$

$=\left(\frac39\times\frac{83-8}{90}\right)\div$$\left(0.5\times\frac19\right)+$$\frac{35-3}{90}\div\frac8{90}$

$=\left(\frac39\times\frac{75}{90}\right)\div$$\left(\frac5{10}\times\frac19\right)+$$\frac{32}{90}\div\frac8{90}$

$=\left(\frac3{3\times3}\times\frac{5\times15}{6\times15}\right)\div$$\left(\frac5{2\times5}\times\frac19\right)+$$\frac{16\times2}{45\times2}\div\frac{4\times2}{45\times2}$

$=\left(\frac13\times\frac56\right)\div$$\left(\frac12\times\frac19\right)+$$\frac{16}{45}\div\frac4{45}$

$=\frac5{18}\div\frac1{18}+\frac{16}{45}\div\frac4{45}$

$=\frac5{18}\times\frac{18}1+\frac{16}{45}\times\frac{45}4$

$=\frac5{\cancel{18}}\times\frac{\cancel{18}}1+\frac{\displaystyle\overset4{\bcancel{16}}}{\cancel{45}}\times\frac{\cancel{45}}{\bcancel4}$

$=5+4$

$=9$

নির্ণেয় সরল সমাধান: $9$